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What are the poss. for two 66% leu #102002
05/11/06 12:01 PM
05/11/06 12:01 PM

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I was wondering what the chance would be of two 66% lue het being together of producing a leu? would it be better to get 100% leu het or does it really make a difference?
<img src="/ubbthreads/images/graemlins/nixweiss.gif" alt="" />

Re: What are the poss. for two 66% leu [Re: ] #102003
05/11/06 12:06 PM
05/11/06 12:06 PM

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I don't know the answer to that, but what is a leu het? I've never heard of that type of glider before.

Re: What are the poss. for two 66% leu [Re: ] #102004
05/11/06 12:20 PM
05/11/06 12:20 PM
Joined: Sep 2003
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IL (St. Louis area)
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Leucistic gliders are the black eyed white gliders. A leucistic het (leu het) is a sugar glider that carries the leucistic gene, but does not display it.


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Re: What are the poss. for two 66% leu [Re: ] #102005
05/11/06 12:34 PM
05/11/06 12:34 PM

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Oh. Thanks. There's so many different gliders, it's so hard to keep up with them all. lol.

Re: What are the poss. for two 66% leu [Re: ] #102006
05/11/06 01:45 PM
05/11/06 01:45 PM

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you have a 66% chance for each of the pair to carry the gene to produce a bew. 100% is guarnateed to carry the gene to make bew joeys. But that is why they are more expensive.

Re: What are the poss. for two 66% leu [Re: RSXTC] #102007
05/12/06 10:53 AM
05/12/06 10:53 AM

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thanks that actually makes sense lol
so what if i have a 100% leu het and a reg leucistic would that then be 50/50?

Re: What are the poss. for two 66% leu [Re: ] #102008
05/12/06 11:00 AM
05/12/06 11:00 AM

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I don't know what the percentage is that you will get bew joeys, but I do know you will get them with that pairing. <img src="/ubbthreads/images/graemlins/smile.gif" alt="" /> When you see the percentage for a leu het it is refering to how likely it is to carry the gene. Not how often they will have bew joeys. Judie or Sheila would be able to give you a better guess of how often a 100% het and a Leu have leu joeys. For me I am batting 50/50 and so is my sister.

On a side note once a lower percentaged het (other then 100%) proves that they do make bew joeys they are then concidered 100% het.

Re: What are the poss. for two 66% leu [Re: ] #102009
05/14/06 11:28 AM
05/14/06 11:28 AM
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66% Possible Leu Het = 2/3 of the offspring will be 100% Leu Hets. 1/3 will not carry the white gene.

100% Leu Het x 100% Leu Het ratio of producing BEW is 1:4

100% Leu Het x BEW ratio of producing BEW is 1:2

BEW x BEW ratio of producing BEW is 1:1

Because all of the BEW's are related... established breeders are not pairing the BEW's together.

Re: What are the poss. for two 66% leu [Re: ] #102010
05/14/06 12:05 PM
05/14/06 12:05 PM

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Leucistic is a recessive gene and therefore it needs two copies of the allele to show the phenotype. A Punnet square can be used to give the probability of seeing a specific genotype. A gene is composed of two alleles; one allele originates from both parents. Because this is a recessive gene it requires two copies of the recessive to show the phenotype. If you pair two leucistics together each parent will only be able to pass the leucistic allele and so the offspring will always be leucistic since it will get both copies from its parents. A 100% het for leucistic has one wild type allele and one leucistic allele so there is a 50% chance of passing either of these alleles on to the offspring from the parents. A glider either carries a gene or it does not. For leucistic there are no degrees of expression it either is or is not a leucistic. What is meant by a 66% possible leucistic is that both parents were 100% leucistic hets. They can produce 4 types of genotypes and they are: ll (leucistic), Ll (het for leucistic), lL (het for leucistic), and LL (normal). The only recognizable genotype is the leucistic so that if you get a normal looking glider you know it will have one or more copies of the wild type allele. So you can eliminate the genotype ll and that leaves you with three possibilities for the genotype, two of them are het for leucistic and one of these is wild type. That means that 2/3, or 66% (actually 67% when you round up) of the offspring carrying the leucistic gene. That is a 66% het for leucistic. A 50% het for leucistic is produced from a 100% het for leucistic and a normal. The possible genotypes for the offspring produced from this pairing are: LL (wild type), LL (wild type), Ll (het for leucistic), and lL (het for leucistic). Because you cannot distinguish the wild type gliders from the het for leucistic gliders you are only able to give a probability of the joeys being het. Two out of four of the possible genotypes is het for leucistic so that gives you a 50% probability of producing a het for leucistic, and that is why these types of gliders are called 50% het for leucistic. If you want to learn how to do a Punnet square you can go to this website and it gives a very detailed explanation, much better than I could describe in words.

Mendelian Genetics

Re: What are the poss. for two 66% leu [Re: ] #102011
05/14/06 01:16 PM
05/14/06 01:16 PM

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Thanks everyone i so remember genetics somehow lol from highschool and the punet square so i do understand all of that but let me get this
if you have a reg glider from pairing a leu and a 100 leu together then the babies would be 100% het for leu correct?
thanks so much for all of your help

Re: What are the poss. for two 66% leu [Re: ] #102012
05/14/06 03:32 PM
05/14/06 03:32 PM

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That is correct. Every joey from a leucistic parent will carry the leu gene. Therefore all offspring from a leu will be 100% leucistic hets.

Re: What are the poss. for two 66% leu [Re: ] #102013
05/14/06 10:52 PM
05/14/06 10:52 PM

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except for those gliders that are a leucistic


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